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0.386x^2+1.665x-41.995=0
a = 0.386; b = 1.665; c = -41.995;
Δ = b2-4ac
Δ = 1.6652-4·0.386·(-41.995)
Δ = 67.612505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.665)-\sqrt{67.612505}}{2*0.386}=\frac{-1.665-\sqrt{67.612505}}{0.772} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.665)+\sqrt{67.612505}}{2*0.386}=\frac{-1.665+\sqrt{67.612505}}{0.772} $
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